M. Bison, post: 81035, member: 359 Wrote:98+99+88+87+79 = 451 which divided by 500 is less than 1. The datatype is an int which means anything beyond the integer is dropped, making it 0. The result is 0 * 100 = 0.

Try this:

Code:

#include<stdio.h>
int main()
{
int m1,m2,m3,m4,m5,per;
printf("Enter the marks of five subjects\n");
scanf("%d%d%d%d%d",&m1,&m2,&m3,&m4,&m5);
per=(int)(((float)(m1+m2+m3+m4+m5))/500.0*100.0);
if(per>=80)
printf("First Division\n");
else if(per>=60)
printf("Second Division\n");
else if(per>=50)
printf("Third Division\n");
else
printf("Fail");
return 0;
}

PS: If you intend on rounding to the nearest integer, add 0.5 before the cast to int.

M. Bison, post: 81035, member: 359 Wrote:PS: If you intend on rounding to the nearest integer, add 0.5 before the cast to int.

Danger255, post: 81078, member: 14867 Wrote:Please can u explain this further?

Spartacus, post: 81083, member: 1060 Wrote:why not just define the number variables as

float m1,m2,m3,m4,m5,per;

M. Bison, post: 81277, member: 359 Wrote:Why isn't anyone else replying anymore?

M. Bison, post: 81277, member: 359 Wrote:

Code:

#include <stdio.h>
int main()
{
char another;
int num;
do
{
printf("Enter a number\n");
scanf("%d",&num);
printf("Square of %d is %d\n",num,num*num);
printf("Want to enter another number? y/n\n");
scanf(" %c",&another);
} while(another=='y');
return 0;
}

Spartacus, post: 81319, member: 1060 Wrote:Danger, just remember you can't let Bison keep on doing your homework for you.

You have to figure some things out yourself if you want to learn the language better.

i miss programming..too bad i'm too much of a noob to do anything special or unique.