Jul 23 2013, 05:07 AM
Jul 23 2013, 05:08 AM
Moriarty, post: 98813, member: 9168 Wrote:I forgot to say not to use Google.
hahahahaha
Jul 23 2013, 05:11 AM
DareDevil, post: 98814, member: 16627 Wrote:hahahahahaIt's good that you find your stupidity and unwillingness to accept the challenge funny. It was for people who can think. Just shoot yourself. Jay can you remove his post? He copy pasted from Wikipedia.
Jul 23 2013, 05:13 AM
Moriarty, post: 98815, member: 9168 Wrote:It's good that you find your stupidity and unwillingness to accept the challenge funny. It was for people who can think.
Potassium mate, I do lots of solves with my classic DaYan Zhanchi cube.. Nuff said :p
Jul 23 2013, 05:15 AM
Can you remove your post? Just click edit and remove the answer. It is not nice. If you don't wish to use your brain let others do it. Please.
Jul 23 2013, 05:18 AM
EH? okay. :-(
Jul 23 2013, 05:40 AM
Moriarty, post: 98807, member: 9168 Wrote:He might.
Here is another Math problem:
9 balls. They all have the same shape, color, etc. The only difference is that one of the balls is a little bit heavier than the rest, by so little, that you can't even tell. The rest 8 are equal. You have a classic scales like the ones in the picture. You can only use the scales twice to figure out which ball is heavier. Go ahead.
A problem solver, oh goodie.
Does it count if I knew this puzzle already? D:
Jul 23 2013, 05:48 AM
xXThatNubXx, post: 98821, member: 16818 Wrote:A problem solver, oh goodie.You know what, don't care. Wrong place. Go get some frags.
Does it count if I knew this puzzle already? D:
Jul 23 2013, 09:16 AM
Jul 23 2013, 10:10 AM
Yes it is 20, don't/didn't you go to school guys o_O
First round put 3 on each side. If one side is heavier, then take those 3 for the 2nd weighing. If they stay the same, take the 3 that weren't weighed for the next round.
Second weighing, put 1 on each side, whichever is heaviest is that ball. If it's the same, it's the ball that you left out.
Fin.
First round put 3 on each side. If one side is heavier, then take those 3 for the 2nd weighing. If they stay the same, take the 3 that weren't weighed for the next round.
Second weighing, put 1 on each side, whichever is heaviest is that ball. If it's the same, it's the ball that you left out.
Fin.